Easy percentage prob (for pro) hahah

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To determine the natural percent abundance of lithium's heavier isotope, one can set the proportion of the heavier isotope as "x" and the lighter isotope as "1 - x." Using the average atomic weight of lithium (6.941) and the mass numbers of the isotopes (6.015 and 7.016), an equation can be formulated. By solving this equation, the percent abundance of the heavier isotope can be calculated. This method provides a systematic approach to solving the problem.
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Homework Statement



Lithium has an average atomic weight of 6.941. If the only two stable
isotopes have mass numbers of 6.015 and 7.016, what is the natural
percent abundance of the heavier isotope?




Homework Equations



any help would be good. thanks ( ican do it easy when they give percent but this is different

The Attempt at a Solution

 
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geffman1 said:
Lithium has an average atomic weight of 6.941. If the only two stable
isotopes have mass numbers of 6.015 and 7.016, what is the natural
percent abundance of the heavier isotope?

Hi geffman1! :smile:

General technique … give the answer a letter, and use that letter to get an equation.

in this case, call the proportion of the heavier isotope "x" (so the proportion of the lighter isotope is 1 - x), and write an equation. :wink:
 
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