EASY PROBLEM - Force to break the string.

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Homework Help Overview

The problem involves calculating the force required to break a string while whirling a toy whistle in a horizontal circle. The subject area includes concepts from dynamics and circular motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between frequency, angular velocity, and centripetal force. There are attempts to derive the necessary equations and clarify the steps needed to find velocity from the given revolutions per second.

Discussion Status

Participants are actively engaging with the problem, with some providing insights into the calculations needed. There is a recognition of confusion regarding the use of a calculator and the interpretation of the problem setup. Multiple interpretations of the approach are being explored.

Contextual Notes

Some participants express uncertainty about the initial conditions and calculations, indicating potential misunderstandings of the problem's requirements. There is mention of specific values and units that may need clarification.

8parks11
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A .208-kg toy whistle can be whirled in a horizontal circle of 1.00 m radius at a maximum of 3.00 rev/s b4 the string breaks. What is the force needed to break the string.

I don't know how to start this problem but this is what i got.

first i found frequency which is 1/3
and then i got omega = 2pi 1/3

i think this is all wrong because the answer is 73.9N

someone please help!
 
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ook i read the problem wrong so it should be
f=mac
and then f=mv^2/r
so iget 0.208 x v^2 / 1
now how do i get v from the maximum revolution
 
ok i got one revolution is 2pi (obviously)
how do i implement that tothe problem to solve it.
 
If 1 rotation is 2pi, how far does it travel in 1 second? This is the velocity.
 
ok now i got everything I am screwing up with this ti-89
i did 6pi^2 which obviously registered as pi^2 x 6
thanks
 
Last edited:
ok now i got everything I am screwing up with this ti-89
i did 6pi^2 which obviously registered as pi^2 x 6
thanks
 

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