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Easy problem that I am stuck on

  • Thread starter azila
  • Start date
  • #1
67
0
Easy problem that I am stuck on....

Homework Statement


Two vectors A and B have magnitude of A = 3.02 B=3.00. Their vector product is AXB = -4.90k + 2.01i. What is the angle between vector A and vector B?


Homework Equations


since I know the vector product of A and B, I was thinking that Cx = 2.01 and Cz = -4.90. I would then add them together to get -2.89. Then could i use the equation C = ABsin(theta). That would be like

-2.89 = (3.02)(3.00)sin(theta)
-.319=sin(theta)
-18.6 = theta
I don't know if this is the right path to follow but this is what I could come up with.


The Attempt at a Solution



THANKS for any help.
 

Answers and Replies

  • #2
378
2
it's
[tex]\left| c\right| =\left| a\right| \,\left| b\right| \,sin\left( p\right) [/tex]
where c = a x b
 
  • #3
67
0
so am I solving it incorrectly because i am using the same equation, its just that I don't know if the value of c that I have is correct. Also the answer I get is not right. So, what should I change? thanks for the help though.
 
  • #4
378
2
get the absolute value of c.
c^2=x^2+y^2+z^2
 
  • #5
67
0
Thank You So Much! I Realized What I Was Doing Wrong Was That I Was Taking The Sin When I Should Have Been Taking The Arcsin. Thanks Again!!
 

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