1. The problem statement, all variables and given/known data Two vectors are given by A = 3i + j and = -1i + 2j. A) Find A x B <---This is the cross product not multiplication. B) Find the angle between A and B. 2. Relevant equations |AxB|=|A||B|sin(theta) 3. The attempt at a solution A) I used the determinant to find the cross product as 3(2)-1(-1)=7 <---This answer is correct B) I need help with this problem... I tried |AxB|=|A||B|sin(theta) to get θ= arcsin( |AxB| / ( |A||B| ) |A|=√(Ax^2+Ay^2)=3.16 |B|=√(Bx^2+Ay^2)=2.24 Thus, θ= arcsin(7/((3.16)(2.24)))=81.8 °. However, it says that it is the wrong answer and I don't know why. Can anyone please help? Thank you.