Easy problem that i dont understand

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To describe a transverse wave pulse traveling in the positive x direction at a speed of 2.50 m/s, the function y(x, t) can be derived from the initial function y = 6/(x^2 + 3). The correct approach involves substituting x with (x - vt), where v is the wave speed. Thus, the resulting function is y(x, t) = 6/((x - 2.50t)^2 + 3). This method effectively captures the wave's behavior over time. Understanding this substitution is crucial for solving similar wave problems.
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At t = 0, a transverse wave pulse in a wire is described by the following function where x and y are in meters.

y=6/(x^2+3)


Write the function y(x, t) that describes this wave if it is traveling in the positive x direction with a speed of 2.50 m/s.

all i know that in the positive x direction f(x-vt) is the wavelength...but how is this relevant to this question?

i have no idea how to solve this
 
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nemzy said:
At t = 0, a transverse wave pulse in a wire is described by the following function where x and y are in meters.

y=6/(x^2+3)


Write the function y(x, t) that describes this wave if it is traveling in the positive x direction with a speed of 2.50 m/s.

all i know that in the positive x direction f(x-vt) is the wavelength...but how is this relevant to this question?

i have no idea how to solve this

You know wrong: f(x-tv) is not the wavelength. A wave traveling in the positive x direction is represented by a function f(x-vt).

Your y(x) function is the same as this f(x,t) at t=0.

ehild
 
nemzy said:
At t = 0, a transverse wave pulse in a wire is described by the following function where x and y are in meters.

y=6/(x^2+3)


Write the function y(x, t) that describes this wave if it is traveling in the positive x direction with a speed of 2.50 m/s.

all i know that in the positive x direction f(x-vt) is the wavelength...but how is this relevant to this question?

i have no idea how to solve this
You have all the elements of the answer.
A wave traveling to the right at a speed v is obtained from the shape of the wave at t=0 by replacing x by x-vt. So simply replace x by (x-2.50 t) in your function and you get the function at any time. That's all.

Pat
 
thanks answer is right
 
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