Easy Tips for Describing Vectors | Learn How to Describe Vectors Accurately

  • Thread starter Thread starter vitaly
  • Start date Start date
  • Tags Tags
    Vectors
AI Thread Summary
Describing vectors accurately involves understanding both their magnitude and direction, which can be challenging. To determine the direction, visualize a Cartesian coordinate system and identify the angle of the vector relative to the axes. Techniques such as using a right triangle to apply the Pythagorean theorem or the clock method can aid in finding angles. Online resources like Khan Academy and Math is Fun provide valuable practice and explanations for mastering vector descriptions. With consistent practice and the right strategies, confidence in describing vectors will improve over time.
vitaly
Messages
48
Reaction score
0
I am having problems with describing vectors. I understand the part that vectors have magnitude and direction, but that's not the part I'm having issues with. I can't look at a figure and find out whether or not the vector is, for example, 30 degrees south of east or 30 degrees east of south. Does anybody know a good way to find out how to describe vectors? Or maybe a website I could visit to help me?

Thanks.
 
Physics news on Phys.org
I'm sure there are plenty of websites out there, but none come to mind (try a google search).
Descriptions of vectors such as "30 degrees south of east" only give the direction of the vector and tell us nothing about it's magnitude. This can be seen by setting up a cartesian coordinate system with two axis (the typical x-y grid). Label each end of the axis North, South, East, and West (for example the +y direction could be North, +x could be East, the -y south, and -x west). To obtain a vector pointing 30 degrees south of east, start with an arbitrary non zero position vector pointing east ( in the direction of the +x axis ) and rotate it 30 degrees south (that is toward the -y axis). The resulting vector should have an angle of -30 degrees from the +x axis, and based on this coordinate system we call that 30 degrees south of east.
 


Describing vectors accurately can be challenging, but with some practice and helpful tips, you can improve your skills. One useful tip is to always start by identifying the direction of the vector. This can be done by looking at the figure and determining which way the vector is pointing. Once you have identified the direction, you can then use basic geometry to determine the angle of the vector.

To find the angle, imagine a right triangle with the vector as the hypotenuse. Use the Pythagorean theorem to find the length of the adjacent and opposite sides. The angle can then be found using the inverse tangent function (tan^-1). This will give you the angle in degrees or radians, depending on the calculator you are using.

Another helpful tip is to use the clock method. Imagine the vector as the hour hand of a clock. The direction it is pointing towards will correspond to the hour on the clock. For example, if the vector is pointing towards 3 o'clock, it is 90 degrees east of north.

You can also use online resources such as Khan Academy or Math is Fun to practice and improve your vector description skills. These websites offer explanations, examples, and interactive activities to help you understand and describe vectors accurately.

Remember, practice makes perfect. Keep practicing and using these tips, and you will become more confident in describing vectors accurately. Don't get discouraged if it takes time to master this skill. With patience and persistence, you will get there. Good luck!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top