Eek Integrals are ruining my life.

  • Thread starter Thread starter ashleyk
  • Start date Start date
  • Tags Tags
    Integrals Life
ashleyk
Messages
22
Reaction score
0
Hey I have a test soon and need help on two problems, please!

first is taking the integral of (e^(x)^1/2)/(x)^(1/2) dx



second is taking the integral of 2/(x^2+4x+8) dx


thanks for any help!
 
Physics news on Phys.org
You have to at least show you attempted the problem(s) or the smart people won't want to help.
 
For the 1st one i am not sure where to start...




for the second one, i tried using partial fractions but i could not factor it
 
ashleyk said:
For the 1st one i am not sure where to start...

When in doubt, try a substitution.


ashleyk said:
for the second one, i tried using partial fractions but i could not factor it

It has no real roots. Try completing the square and remember arctan.
 
Hint for the first

2 \frac{d}{dx} e^{\sqrt{x}} =\frac{e^{\sqrt{x}}}{\sqrt{x}}

Daniel.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top