Effect of Sudden Radial Velocity Change on Orbital Energy and Angular Momentum

AI Thread Summary
A communications satellite in a circular orbit experiences a sudden outward radial velocity change due to a rocket firing, which affects its energy and angular momentum. The new energy can be calculated using the formula that incorporates both tangential and radial velocities, while the angular momentum remains unchanged due to the absence of tangential velocity change. The subsequent motion of the satellite will not maintain a constant radius, indicating a transition to an elliptical orbit. The effective potential and kinetic energy must be analyzed to understand the new orbital dynamics post-firing. This scenario highlights the relationship between radial velocity changes and orbital mechanics.
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A communications satellite is in a circular orbit around Earth at radius R and velocity v. A rocket accidently fires quite suddenly, giving the satellite an outward radial velocity v in addition to its original velocity.

a) Calculate the ratio of the new energy to the old and new angular momentum to the old.

b) Describe the subsequent motion of the satellite and plot T(r), V(r), U(r), and E(r) after the rocket fires.

I'm not sure how to do this question.

For a) E = 1/2*mu*v^2 + L^2/(2*mu*R^2) - k/R where mu is reduced mass, L is angular momentum k = G*m1*m2, and E is the total energy.

The v in the first term is for radial velocity only, so it is zero initially because there is no radial velocity in a circular orbit. The energy after the rocket fires, but before any radial position change is equal to the equation as written.

For angular momentum to change without any additional tangential velocity there has to be a radial position change. But I'm not sure how to figure out the radius of the new orbit that the satellite would attain.

For b) T(r) is the kinetic energy, I'm not sure how to plot this since the kinetic energy has a dependence on the derivative of r.

V(r) is the effective potential, consisting of the second two terms in the above energy equation.

U(r) is just the gravitational potential energy.

E(r) is the total energy.


Could someone help please?
 
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asrodan said:
A communications satellite is in a circular orbit around Earth at radius R and velocity v. A rocket accidently fires quite suddenly, giving the satellite an outward radial velocity v in addition to its original velocity.

a) Calculate the ratio of the new energy to the old and new angular momentum to the old.
The new energy is:

E = U(R) + \frac{1}{2}m(v_t^2 + v_r^2)

where v_t is tangential (original) speed and v_r is the radial speed immediately after the rocket fired.

Since the force of the rocket was entirely in the radial direction, was there any torque applied? What does that tell you about angular momentum?

b) Describe the subsequent motion of the satellite and plot T(r), V(r), U(r), and E(r) after the rocket fires.

Using the effective potential:

V_{eff}(r) + T(r) = E(r) where

V_{eff}(r) = U(r) + \frac{L^2}{2mr^2}

and the radial kinetic energy,

T(r) = \frac{1}{2}mv_r^2

For circular orbit, T(r) = 0. Since T(r) is non-zero, what does this tell you about the kind of orbit? Does it have a constant radius?

AM
 
Thanks Andrew.
 
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