Efficiency in a thermodynamic cycle

AI Thread Summary
The discussion focuses on calculating the efficiency of a thermodynamic cycle for an ideal gas, specifically during the a-b stage. The user attempts to apply the Gibbs equation and derives the heat transfer as dQa-b=cvdT+PdV, ultimately finding ΔQ=Wa-b=3P0V0/4. However, there is uncertainty about whether to consider ΔT=0, despite dT being non-zero. Participants suggest calculating the variation of Q along the a-b path to determine if it changes sign. The conversation emphasizes the need for clarity in the calculations to accurately assess the cycle's efficiency.
Alexandre Ricardo
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I have to calculate the efficiency of the above cycle for an ideal gas, that goes at the order a-b-c-a:
CYCLE.png

I know that the answer is 16/97 but I can't calculate the heat in the a-b stage.
 

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Alexandre Ricardo said:
I have to calculate the efficiency of the above cycle for an ideal gas, that goes at the order a-b-c-a:
View attachment 225655
I know that the answer is 16/97 but I can't calculate the heat in the a-b stage.
Let's see what you have done in detail for the a-b stage.
 
Chestermiller said:
Let's see what you have done in detail for the a-b stage.
Right. I started using the Gibbs equation:
$TdS=PdV+dU$
Using the relation:
∂U/∂v|T=T∂P/∂T|v-P

And making some manipulations I obtained:

dQa-b=cvdT+PdV

Considering an ideal gas. Using the ideal gas state equation, ΔT=0 and PdV=Wa-b.

And I found ΔQ=Wa-b=3P0V0/4

But i think there is something wrong in my calculations and I don't know if I would consider ΔT=0 (even if dT≠0)
 
Alexandre Ricardo said:
Right. I started using the Gibbs equation:
$TdS=PdV+dU$
Using the relation:
∂U/∂v|T=T∂P/∂T|v-P

And making some manipulations I obtained:

dQa-b=cvdT+PdV

Considering an ideal gas. Using the ideal gas state equation, ΔT=0 and PdV=Wa-b.

And I found ΔQ=Wa-b=3P0V0/4

But i think there is something wrong in my calculations and I don't know if I would consider ΔT=0 (even if dT≠0)
Calculate the variation of Q along the path a-b, and see how it varies. Does it change sign along the way?
 
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