Efficiency of a cycle from a diagram

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SUMMARY

The discussion focuses on calculating the efficiency of a heat machine using the Carnot cycle diagram in the S-T plane. The efficiency formula discussed is ε = ΔW/ΔQ, with ΔQ evaluated through various processes. The user initially struggles with the evaluation of ΔQ for process 1 but ultimately arrives at the correct efficiency formula ε = (T1 - T2) / (T1 + T2) after considering the integral form of ΔQ = ∫TdS. This highlights the importance of understanding the relationship between temperature and entropy in thermodynamic cycles.

PREREQUISITES
  • Understanding of Carnot cycle principles
  • Familiarity with thermodynamic equations, specifically ε = ΔW/ΔQ
  • Knowledge of entropy and its relation to heat transfer
  • Ability to interpret S-T plane diagrams
NEXT STEPS
  • Study the derivation of the Carnot efficiency formula
  • Learn about the integral form of heat transfer, ΔQ = ∫TdS
  • Explore different thermodynamic cycles beyond the Carnot cycle
  • Investigate the implications of temperature changes on efficiency in heat engines
USEFUL FOR

Students of thermodynamics, engineers working with heat engines, and anyone interested in the principles of energy efficiency in thermal systems.

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Homework Statement


Calculate the efficiency of the heat machine that is shown in the figure. Draw the corresponding Carnot cycle diagram in the S-T plane.


Homework Equations


[itex]\varepsilon = \frac{ \Delta W}{\Delta Q}[/itex].
[itex]\Delta Q = T \Delta S[/itex]

The Attempt at a Solution


My problem lies in evaluating [itex]\Delta Q[/itex] for the process 1 (or from A to B).
For the process 2, [itex]\Delta Q=T_2(S_2-S_1)[/itex].
For the process 3, [itex]\Delta Q=0[/itex] because there's no change in entropy.
But I'm stuck at process 1. My attempt was [itex]\Delta Q=\Delta T \Delta S=(T_2-T_1)(S_2-S_1)[/itex] but I know this doesn't make any sense.
Using that non sensical result I find [itex]\varepsilon = \frac{1}{T_2-\frac{T_2^2}{T_1}}[/itex] which makes no sense because if [itex]T_1=T_2[/itex] I get an infinite efficiency while I should get 0. A friend of mine reached [itex]\varepsilon =\frac{T_1-T_2}{T_1+T_2}[/itex] but I don't know how he did nor if that's right either.
Any help is appreciated.
 

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Did you consider that ##dQ=TdS##, and that if T changes with S that then ##ΔQ=∫TdS##?
 
I like Serena said:
Did you consider that ##dQ=TdS##, and that if T changes with S that then ##ΔQ=∫TdS##?
Actually not! haha.
Now I reach the same answer as my friend. Thank you very much for that. :biggrin:
Hmm I'll think about the Carnot cycle. If I need help I'll post here.
 

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