What Is the Electric Field Magnitude in the Copper Section of a Composite Wire?

[aeris]

Efield in Composite Wire..Pls help!

Homework Statement

A 2.0m length of wire is made by welding the end of a 1.2m long silver wire to the end of an 0.8m long copper wire. Each piece of wire is 0.60mm in diameter. The wire is at room temperature. A potential difference of 5.0V is maintained between the ends of the 2.0m composite wire. What is the magnitude of E in the copper?

Homework Equations

E='roe'J , 'roe' is resistivity
J=I/A, A is cross sectional area
I= 45amperes
A= 2.827*10^-7 sqm

Resistivity of copper= 1.72*10^-8
Resistivity of silver= 1.47*10^-8

The Attempt at a Solution

I tried to calculate J first by substituting in values of I and A using the formula J=I/A and multiplying by 'roe'_copper but i still can't get the right answer! I would like to ask the concept behind the E of a composite wire too..

 

[Kurdt]

First, if you could post what you've done it might be easier to spot a mistake. Secondly what value were you using for I?

 

[aeris]

Mmm.. i found out that I=45amperes and A=2.827*10^-7 sqm and found out that J=1.59*10^8. To find E in copper section i multiplied this J by 'roe'_copper= 1.72*10^-8 to get E=2.74V/m. But the answer is wrong. thanks!

 

[Kurdt]

When I work out the current I get something different. I take it you found current by:

$$I = \frac{VA}{\rho l}$$

 

[aeris]

Yup i found it by using this formula whereby i added the resistance of each component using their respective length and 'roe' since they are in series before dividing 5V with the total resistance to get 45amperes.
i obtained J by I/A, where I=45amperes and A= 2.827*10^-7 sqm to get J=1.59*10^8 A/m^2.
I can't get the idea of finding E using E= 'roe'_copper*J to find E in copper section though.

 

[Kurdt]

It could just be that you are using the wrong resistivity for silver. It is listed as 1.59x10^-8 elsewhere.