Eigenvector with Complex Eigenvalues - What am I doing wrong?

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SUMMARY

The discussion focuses on the calculation of eigenvectors with complex eigenvalues, specifically addressing a common mistake in the ordering of components. The matrix presented is \bmatrix 1 + i & 1 \\ -2 & -1 + i \endbmatrix, which leads to the eigenvector calculation. The correct eigenvector derived from the discussion is (1, -1 - i), which can be transformed to (i, 1 - i) by multiplication with the imaginary unit i. This highlights the importance of careful component arrangement in complex eigenvalue problems.

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Homework Statement


eigenvector.png

Homework Equations


Conjugate of a complex number
Matrix reduction

The Attempt at a Solution



My attempt is bordered. Sorry about the quality.
snapshot.jpg


So I'm not sure what I'm missing. I use the exact same method that I use for normal eigenvectors, just with complex numbers in the mix.
 
Last edited:
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You messed up in the last step and swapped x1 and x2. If you let x2=1, then your equation gave you x1=-1/2+1/2 i. In the vector, however, you have the two values in the other order.
 
I can't quite read all of your work, but if you subtract \lambda along the diagonal, you get:

\bmatrix<br /> 1 + i &amp; 1 \\<br /> -2 &amp; -1 + i \\<br /> \endbmatrix x = 0

The rows of this matrix are multiples (-1 + i) of each other, so you can use either row to find the eigenvector:

x_1 (1 + i) + x_2 = 0
-x_1 (1 + i) = x_2

so your vector is (1, -1 - i). This happens to not be one of your choices, but you can multiply it by i to obtain (i, 1 - i).
 
Last edited:
@vela Thanks. I wasn't really thinking it through at the end.
 

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