Einstein's Mass-Energy Relation Explained

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Einstein's mass-energy relation, expressed as E = mc^2, indicates that mass is a form of energy, with E representing energy, m representing mass, and c denoting the speed of light (approximately 3.0 x 10^8 m/s). The equation quantifies the amount of mass-energy stored in an object, which can be transformed into kinetic energy when the object is in motion. This relation holds true primarily for objects at rest or moving at low speeds relative to light. For objects in motion, the kinetic energy is described by a more complex equation, E = mc^2(1/(1-v^2/c^2)-1), which simplifies to E = mc^2 when velocity (v) is zero. Understanding this relationship is crucial for grasping the principles of physics related to energy and motion.
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somebody explain me einstein mass energy relation
 
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E = mc^2, there E is energy, m is mass, and c is the speed of light (3.0x10^8m/s)
 
Mass is a form of energy. The amount of mass-energy "stored" in an object is given by E = mc^2. So when the mass-energy is transformed into motion (kinetic) energy, the resulting system will have mc^2 amount of kinetic energy.
 
Note that the enery-mass relation is only true if the object is stationary or traveling at a relative low speed compare to light. In general, the kinetic energy for an object is

E=mc^2(1/(1-v^2/c^2)-1), so when v=0, E=mc^2.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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