Elastic Collision of 89.5kg & 25.5kg Skaters - Kevin & Brother

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SUMMARY

The discussion centers on calculating the speed of Kevin, who has a mass of 89.5 kg, just before he grabs his younger brother weighing 25.5 kg while skating. The correct approach involves applying the principle of conservation of momentum rather than incorrectly using the kinetic energy equation. The final speed of Kevin before the collision is determined to be 2.55 m/s, which resolves the confusion surrounding the incorrect repeated answer of 2.41 m/s.

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Homework Statement

Kevin has a mass of 89.5 kg and is skating with in-line skates. He sees his 25.50 kg younger brother up ahead standing on the sidewalk, with his back turned. Coming up from behind, he grabs his brother and rolls off at a speed of 2.13 m/s. Ignoring friction, find Kevin's speed just before he grabbed his brother.

Homework Equations



1/2m1v012+1/2m2v022=1/2m1vf12+1/2m2vf22

The Attempt at a Solution



I have tried many ways of doing this problem, and I keep arriving at the same answer: 2.41 m/s which is incorrect. I then decided to pretend that the kid and his brother are one unit so i added their masses together multiplied times the 2.132 divided by 2 and set that equal to the left side of the above equation. However i again got 2.41. It seems that every way i try this problem i get 2.41

What am i doing wrong?
 
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spidey12 said:

Homework Statement

Kevin has a mass of 89.5 kg and is skating with in-line skates. He sees his 25.50 kg younger brother up ahead standing on the sidewalk, with his back turned. Coming up from behind, he grabs his brother and rolls off at a speed of 2.13 m/s. Ignoring friction, find Kevin's speed just before he grabbed his brother.

Homework Equations



1/2m1v012+1/2m2v022=1/2m1vf12+1/2m2vf22

The Attempt at a Solution



I have tried many ways of doing this problem, and I keep arriving at the same answer: 2.41 m/s which is incorrect. I then decided to pretend that the kid and his brother are one unit so i added their masses together multiplied times the 2.132 divided by 2 and set that equal to the left side of the above equation. However i again got 2.41. It seems that every way i try this problem i get 2.41

What am i doing wrong?

Aren't you supposed to be conserving momentum? Isn't that simply m x v ?
 
Last edited:
LowlyPion said:
Aren't you supposed to be conserving linear momentum? Isn't that simply m x v ?
I am an idiot. I read waaaay to much into this problem. I got it. Thank you.
 

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