Elastic Potential- Acceleration with springs

AI Thread Summary
A 1.6kg mass suspended from a spring in a stationary elevator stretches 12cm, and when the elevator accelerates upwards, the spring extends an additional 12cm. To find the elevator's acceleration, the equation Fy = ma_y is used, where the net force on the system is expressed as kx - mg = ma_y. The spring constant k is first calculated using k = (mg)/x, yielding k = 130.666 N/m. Substituting this value back into the equation allows the determination of the elevator's acceleration, which is found to be approximately 9.8 m/s². The discussion emphasizes the importance of correctly calculating the spring constant before solving for acceleration.
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Homework Statement


A 1.6kg mass is suspended from a spring inside a stationary elevator. The spring stretches 12cm. The elevator now accelerates upwards, and the spring extends a further 12cm. What is the elevator's acceleration?


Homework Equations


Fy= may
Ue= 1/2 (kx2)

The Attempt at a Solution


I'm just not sure on the best way to start this question.
 
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I would start with the first equation you provided. F_y = ma_y. What's the acceleration (a_y) in this problem? Where you can find a force on the system?
 
Fy=may
kx-mg=may
ay=(kx-mg)/m

but k is not given...
 
You need to find k first. What's the spring doing BEFORE the elevator starts moving?
 
Fy=may
kx-mg=0
k=(mg)/x
k=1306.666 N/m

Fy=may
kx-mg=may
ay=(kx-mg)/m
ay=9.79999 m/s2
 
I got a different value for k, could you double check it? My answer was a magnitude different.
 
oops, so k=130.666 N/m
 
Right, and you also know the distance so now would be a good time to find the potential.
 
Looks to me like you're done. No need for the potential in this problem.
 
  • #10
Ah, yep. I was hasty.
 
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