Electric arc: How to calculate the required voltage for a light bow?

AI Thread Summary
To calculate the required voltage for an electric arc between two iron nails separated by 3 cm, it is commonly stated that approximately 1 kV is needed per mm of distance. This means that for a 3 cm gap, around 30 kV would be necessary. The discussion references Paschen's Law, which provides a formula for calculating breakdown voltage in gases. Participants are encouraged to share their backgrounds in high voltage work for better context. Understanding these principles is crucial for safely generating electric arcs.
Hans42
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<Moderator's note: Moved from a homework forum.>

Calculate the required voltage to produce a electric arc between 2 iron nails (distance: 3cm).

I´ve read in the internet that you need 1 kV per mm. But how can I calculate this value, that I need 1kV per 1mm?
 
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Hans42 said:
<Moderator's note: Moved from a homework forum.>

Calculate the required voltage to produce a electric arc between 2 iron nails (distance: 3cm).

I´ve read in the internet that you need 1 kV per mm. But how can I calculate this value, that I need 1kV per 1mm?
Welcome to the PF. :smile:

See if this helps: https://en.wikipedia.org/wiki/Paschen's_law

What is your background in working with high voltages?
 
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