Electric Circuit: Find Voltage Req'd to Charge Battery

AI Thread Summary
To charge a battery with an emf of 24 V and an internal resistance of 0.25 ohms at a rate of 24 A, the required voltage can be calculated using the formula V = emf + Ir. Substituting the values, V equals 24 V plus (24 A multiplied by 0.25 ohms), resulting in a total of 30 V. This calculation confirms that 30 V is indeed the correct voltage needed for charging. The discussion emphasizes the importance of using the correct formula for charging scenarios. The conclusion is that the voltage required to charge the battery is 30 V.
Jabababa
Messages
52
Reaction score
0

Homework Statement



A battery has an emf of 24 V and an internal resistance of 0.25 ohm is being charged at a rate of 24 A. What is the voltage required to do this?

Homework Equations



V(terminal) = emf +/- Ir

The Attempt at a Solution



Since the battery is getting charged that means we use the V= emf + Ir

V = 24 + (24)(0.25) = 30V

Is this correct?
 
Physics news on Phys.org
Jabababa said:

Homework Statement



A battery has an emf of 24 V and an internal resistance of 0.25 ohm is being charged at a rate of 24 A. What is the voltage required to do this?

Homework Equations



V(terminal) = emf +/- Ir

The Attempt at a Solution



Since the battery is getting charged that means we use the V= emf + Ir

V = 24 + (24)(0.25) = 30V

Is this correct?
Yes.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Why is source force + electrostatic force = 0 inside battery?
Replies
10
Views
1K
Mechanisms Involved When Charging a Battery
Replies
10
Views
1K
Circuit with potential difference across battery being zero?
Replies
3
Views
1K
Why do the headlights on the car become dim when the car is starting?
Replies
4
Views
2K
Internal Resistance of a Car Battery
Replies
8
Views
13K
Ohm's Law - Finding Source Voltage
Replies
3
Views
1K
Potential difference between 2 points in a capacitor circuit
Replies
30
Views
2K
Current through a circuit when the key is open
Replies
42
Views
5K
Help in solving an electricity circuit problem involving Kirchoff's law
Replies
7
Views
2K
How does a simple circuit work?
Replies
12
Views
1K

Hot Threads

Recent Insights

Back
Top