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kong12
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What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 6900 N/C and is directed due north?
An electric field is a physical quantity that describes the force exerted on a charged particle by other charged particles in its vicinity. It is a vector field, meaning that it has both magnitude and direction, and is measured in units of volts per meter (V/m).
An electric field is created when there is a difference in electric potential between two points. This can be achieved by having a separation of positive and negative charges, or by applying a voltage difference across a conductive material.
The strength of the electric field determines the acceleration of an electron. A stronger electric field will result in a greater force on the electron, causing it to accelerate at a higher rate. This can be described by the equation F = qE, where F is the force, q is the charge of the electron, and E is the electric field strength.
Charged particles in an electric field will experience a force and either be repelled or attracted depending on their charge. This force can cause the particles to accelerate or change direction of motion. In a uniform electric field, the particles will follow a curved path due to the constant force acting on them.
Electric fields and electron acceleration have many practical applications, such as in electronic devices like TVs and computers, where electrons are accelerated to create images on screens. They are also used in particle accelerators for research in physics and medicine, and in electrostatic precipitators to remove pollutants from industrial gases. Additionally, electric fields play a crucial role in the functioning of nerves and muscles in living organisms.