- #1

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- Thread starter kong12
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- #1

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- #2

- 134

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[tex]m \vec{a} = -eE \hat{y} [/tex]

[tex] \vec{a} = \frac{-eE}{m} \hat{y} [/tex]

where e is the charge of the electron and m is its mass.

- #3

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Two point charges, q1 = +20.0 nC and q2 = +11.0 nC, are located on the x-axis at x = 0 and x = 1.00 m, respectively. Where on the x-axis is the electric field equal to zero? i wanted to use the equation E=k[q]/r^2 but i'm confused as to what to do with the x=0 and x=1

- #4

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You can use the x values to determine the distance (r) between the two charges.

- #5

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i am not sure how to encorporate the the one formula with the various values

- #6

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