Electric field at a distance greater than the radius of sphere

AI Thread Summary
To determine the electric field E(r) at a distance greater than the radius of a uniformly charged solid ball, the correct formula involves using the total charge Q and the area of a sphere. The charge Q is calculated as Q = ρ * (4/3)πr_b^3, where ρ is the charge density and r_b is the radius of the ball. The electric field formula should be E(r) = (Q/ε_0) * (1/(4πr^2)), reflecting the area of a sphere, which is 4πr^2, not (4/3)πr^3. The initial misunderstanding about the area and charge calculation was clarified during the discussion. The correct approach leads to the proper expression for E(r) at distances greater than r_b.
rocapp
Messages
95
Reaction score
0

Homework Statement



A solid ball of radius rb has a uniform charge density ρ.

What is the magnitude of the electric field E(r) at a distance r>r_b from the center of the ball?

Homework Equations



E(r) = (Q/ε)*1/Area

The Attempt at a Solution



If Q=ρrb

and Area = (4/3)πr3,

then E(r) = \frac{ρr<sub>b</sub>}{ε*(4/3)*πr<sup>3</sup>}


However,
the correct answer is in the image attached.
E(r)=
=%5Cfrac%7B%7B%5Crho%7D+%7Br_%7Bb%7D%7D%5E%7B3%7D%7D%7B3+%7B%5Cepsilon%7D_%7B0%7D+r%5E%7B2%7D%7D.gif

 
Physics news on Phys.org
Area is not (4/3) pi r^3

Also, Idon't think q = prb
 
Oh. I get it now. Thanks!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top