Electric Field at a Point on the Axis of a Charged Disk?

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SUMMARY

The discussion focuses on calculating the electric field at a point on the axis of a charged disk with a specific surface charge density equation, sigma = (sqrt(r² + 961)) x 10^-6 C/m², where r is the radial distance in meters. The disk has an outer radius of 7 m and an inner radius of 2 m. Participants clarify the notation used in the equation and confirm that 961 is in meters squared. The integration of the electric field contributions from the charged disk is essential for solving the problem.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of surface charge density concepts
  • Ability to interpret mathematical notation in physics
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions
  • Learn about the integration of electric fields for annular disks
  • Explore the application of Gauss's Law in electrostatics
  • Review examples of electric field calculations for varying charge densities
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Homework Statement


A flat, circular annulus of radius 7 m with a hole in the center of radius 2 m is charged on one surface such that the surface charge density varies with the radial distance from the center of the disk by the equation sigma= (r2 + 961)1/2 x 10-6, where is in C/m2 and r is in meters.

Find the magnitude of the electric field at a point on the axis of the disk, a distance 31 m away from the center of the disk.

Homework Equations

disk8.gif

The Attempt at a Solution



Do I combine the equations and integrate from 2 to 7? I am lost...
 
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You write: "sigma= (r2 + 961)1/2 x 10-6". Please clarify. Is that r2 or r2? Is 961 in units of meters or meters2? Is that (r2 + 961) x 1/(2 x 10-6), or is it (r2 + 961) x (1/2) x 2 x 10 - 6? Or something else?
 
r2 is r squared. 961 is meters.
It is (sqrt(r squared + 961))e-6.
 

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