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rahaverhma
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What is the value of electric field at the surface of a spherical shell?
rahaverhma said:I don't mean above the surface. Actually Exactly at the surface. And let radius 'r', charge 'q'.
The electric field at the surface of a spherical shell is a measure of the strength and direction of the electric force experienced by a charged particle placed on the surface of the shell. It is given by the ratio of the electric force to the charge of the particle and is expressed in units of newtons per coulomb (N/C).
The electric field at the surface of a spherical shell can be calculated using the formula E = Q/4πε₀r², where Q is the charge of the shell, ε₀ is the permittivity of free space, and r is the radius of the shell.
No, the electric field at the surface of a spherical shell does not depend on the charge distribution of the shell. It only depends on the total charge of the shell and the radius.
The electric field at the surface of a spherical shell is constant regardless of the distance from the center. This is because the electric field is a result of the charge distribution on the surface of the shell, and this distribution remains the same regardless of the distance from the center.
Yes, the electric field at the surface of a spherical shell can be zero if the total charge of the shell is zero. This means that there are equal amounts of positive and negative charges on the surface, resulting in a net electric field of zero.