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I have a problem with electric fields in capacitors. Using Gauss' Law, we always choose the Gaussian surface that encloses the positive plate in the capacitor. When we go through field calculations, we get an equation for the electric field and we use that to find voltage, capacitance, and everything else. What I don't understand is how enclosing ONLY the positive plate takes into account the fact that the negative plate is present and that it amplifies the field between the two. In other words, how would our calculations or conclusions be any

*different*if the negative plate

*were not even present*?

Thank you very much for the help