Electric field in parallel plate capacitor

AI Thread Summary
The discussion centers on calculating the force acting on a point charge located between the plates of an air-filled parallel plate capacitor. The parameters include a distance of 5mm, an area of 500cm², and a charge of 10nC on the electrodes. The user initially calculates the force as 9.02 N but is informed that the correct answer is 4.52 * 10^-6 N. To find the electric field between the plates, the user is advised to use surface charge density and Gauss' theorem, leading to the correct force calculation using the formula F = EQ', where Q' is the point charge. The discussion confirms that the provided answer is accurate.
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Homework Statement



The parameters of an air-filled parallel plate capacitor are: d = 5mm and A = 500cm2. The
charge of the electrodes are Q = 10nC and −Q. Inside of the capacitor in the middle point
there is a point charge of 0, 02Q. Find the magnitude of the force acting to the point charge!

Homework Equations



I'm guessing these formulas

C=Q/V = ε0 * A/d

V = E*d

The Attempt at a Solution



The answer is supposed to be 4.52 * 10-6 N

However I plug in the values and get 9.02 N.. Am I using the wrong formulas, or am I just calculating it wrong?
 
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You don't want to compute capacitance.

What did you get for the E field between the plates? You can use for example σ = D where σ = surface charge density and D = εE. Or use Gauss' theorem.

Then F = EQ' where Q' = 0.02Q.

The given answer is correct BTW.
 
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