Electric field, magnetic flux , potetial difference

[oportunity]

Homework Statement

As shown in the figure below, potential difference V exists between two parallel plates(a,b) that have a small hole. Uniform electric field E and magnetic flux density B exist in the region above the plates, and are perpendicular to each other. The directionof E is parallel to this page and plate b. The directionof B is perpendicular to this page from back to front. A positiely charged particle of charged q and mass m, initially at res in the hole of plate a, is accelerated by potential difference V so that it enters te region above the plate perpendiculary to E and B and travels straight through the region.
http://imageshack.us/photo/my-images/442/imagenq4.png/
http://imageshack.us/photo/my-images/442/imagenq4.png/

What is the ratio E/B?Thanks

Please tell me how i put images in the post.

 

[Simon Bridge]

Great - so where did you get stuck?
Do you know the equation that relates the force on a charged particle due to electric and magnetic fields?
Do you know how to relate the kinetic energy a charge gains when it falls through a potential difference of V?

 

[oportunity]

you mean lorentz force?

 

[oportunity]

No, i don't know. please tell me.

this is really important. help please.

 

[Simon Bridge]

Are you not doing a course in elecromagnetism that you have notes for? Go read them?

The voltage is the electric potential energy per unit charge ... when the charge travels between the plates, then, it loses potential energy qV and gains kinetic energy - what's the equation? You can do this.

The electric field strength is the force per unit charge ... so \vec{F}_E = q\vec{E}

For the magnetic field, only moving charges experience a force: \vec{F}_B = r(\vec{v} \times \vec{B})

Do you know how to evaluate a cross product? (Hint - v and B are at right angles: it's the right-hand slap rule.)

Now all you need is Newton's Laws.

 

[oportunity]

i get it, thanks a lot.