Electric field near infinite charged sheet and point charge

AI Thread Summary
The electric field near an infinite charged sheet is constant at sigma/2E, independent of distance, due to the uniform distribution of charge. In contrast, the electric field from a point charge increases infinitely as one approaches it because the field lines converge. The charged sheet can be thought of as a combination of point charges, but the average effect remains finite due to the cancellation of forces parallel to the surface. The cone analogy illustrates how the component of force perpendicular to the sheet remains constant, regardless of distance. Understanding these differences is crucial for grasping electric field behavior in electrostatics.
prakharj
Messages
10
Reaction score
0
Electric field near charged sheet is sigma/2E
Which is independent of the distance from it.. However In case of point charge, as we go very close to it, magnitude of electric field tends to infinity.. But why doesn't this happen with charged sheet, i mean it can also be considered as combination of point charge, so while going very close to it, mag. Of electric field must increase, instead of remaining constant..
(please clear me up, I'm new in this area)
thank you.
 
Physics news on Phys.org
hi prakharj! :smile:
prakharj said:
Electric field near charged sheet is sigma/2E
Which is independent of the distance from it.. However In case of point charge, as we go very close to it, magnitude of electric field tends to infinity.. But why doesn't this happen with charged sheet, i mean it can also be considered as combination of point charge, so while going very close to it, mag. Of electric field must increase, instead of remaining constant..
(please clear me up, I'm new in this area)
thank you.

two alternative explanations …

i] the field lines are parallel for a plane charge (so the strength stays the same), but they converge for an isolated charge (so the strength gets larger and larger)

ii] the field does tend to infinity if you approach a charged sheet, but only if you are heading directly towards one of the charges …

most of a charged sheet is empty space, so on average the field stays finite :wink:
 
tiny-tim said:
ii] the field does tend to infinity if you approach a charged sheet, but only if you are heading directly towards one of the charges
In an ideal charged sheet, the charge is uniformly spread so that amount of charge per unit area is constant, so no matter how close you get to the sheet the field remains constant (until you actually reach the surface of the sheet).

The forces (upon a point charge) parallel to the surface of the sheet cancel, so only the component of force perpendicular to the sheet from each point on the sheet affects the field at some point at some distance from the sheet. Say you only consider the portion of the force that is limited to some maximum angle from perpendicular. The shape of this component is a cone with it's circular base at the sheet and it's peak at the point. If you double the distance from the sheet, the inverse square law states the force per unit area is 1/4th of what it was before, but that area of the base of that cone has quadrupled, so that component of force within a cone with some fixed sub-tended angle remains constant regardless of distance from the sheet. Then you can let that subtended angle of the cone increase towards a limit of π, and the effect remains the same.

This cone analogy is one of the ways calculus can be used to calculate the force (the cone analogy is similar to the field from a disk where the ratio of height versus radius is fixed). The force from a thin ring of charge with a fixed charge per unit length of the ring can be calculated, and then the force from an disk composed of an infinite number of thin rings can be calculated, as is done here:

http://hyperphysics.phy-astr.gsu.edu/%E2%80%8Chbase/electric/elelin.html#c3

As R → ∞, the field → k σ 2 π.

The alternative in calculus is to consider the force from an infinitely long thin line with fixed charge per unit length, then calculate the force from an infinite plane made up of an infinite number of those lines.
 
Last edited by a moderator:
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top