Electric Field of a Dielectric Sphere

AI Thread Summary
To find the electric potential at the center of a uniformly charged dielectric sphere, one must determine the electric field both inside and outside the sphere. The electric field inside the sphere is given as Kq/R, while the field outside requires application of Gauss's Law for calculation. The potential difference can be calculated by integrating the electric field from infinity to the sphere's surface and then from the surface to the center. The final result for the electric potential at the center is 6kq/R. Understanding these steps is crucial for solving similar problems involving electric fields and potentials.
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Homework Statement


A uniform charge q is distributed along a sphere of radius R.
a) What is the Electric Potential in the center of the sphere?



Homework Equations


V(r1)-V(r0) = - \int \stackrel{\rightarrow}{E} * \stackrel{\rightarrow}{dl}


The Attempt at a Solution

 
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You will need to find the electric field both inside and outside the field and integrate the expression you posted from infinity to R using the field outside and then from R to zero using the field inside.
 
Thanks for answering, but actually I can't find the expression for the second part of the Electric field

The first is inside the sphere which leads to \frac{Kq}{R} but the Electric field of the outside part of the sphere I don't know what to do

obs: the answer is : \frac{6kq}{R}
 
Use Gauss's Law to find the field in the two regions.
 
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