# Electric Field of a Hollow Cylidrical Conductor

1. Mar 30, 2013

### Zook104

Consider a hollow cylindrical conductor in vacuum with its axis aligned with
the z-axis, and with a positive surface charge density σ. The direction of the
electric field is radial and its magnitude E is only a function of the distance r
from the z-axis, E = E(r).

Use Gauss' law to obtain the magnitude of the electric field at r < R and
at r ≥ R, where R is the radius of the conductor.

I don't know whether I have got my brain stuck in a rut but I can't for the life of me solve this. Any and all help will be greatly appreciated :D

2. Mar 30, 2013

### BruceW

hey, welcome to physicsforums!
Try using Gauss' law, as it says. What kind of Gaussian surface should you use to take advantage of the symmetry?

3. Mar 30, 2013

### Zook104

A cylindrical surface? With surface area of 2$\pi$rl ?

4. Mar 30, 2013

### Zook104

Or should I just use a circular one because the conductor is infinite either side?

5. Mar 30, 2013

### BruceW

Use the cylinder with surface area of 2*PI*r*l
Do the calculation using the information they have given you, and it should all come out nicely. (Even though the conductor is infinite, it doesn't go bad).

6. Mar 30, 2013

### rude man

Go with that one.

7. Mar 31, 2013

### Zook104

Excellent I believe I have got the correct answer :D Thank you so much for your help

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