Electric Field of a Line of Charge

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SUMMARY

The electric field of a line charge at a distance 'a' is expressed as µ/(2Π ε0a), where µ represents the linear charge density. The potential at that point is incorrectly stated as µ/(2Π ε0) based on the assumption that potential equals electric field multiplied by distance. This leads to the conclusion that there is no potential difference around the line of charge, which is incorrect. The correct formula for potential must account for the nature of the electric field and requires a proper derivation, as highlighted by the reference provided in the discussion.

PREREQUISITES
  • Understanding of electric fields and potentials
  • Familiarity with linear charge density (µ)
  • Knowledge of the relationship between electric field and potential
  • Basic calculus for derivations in electrostatics
NEXT STEPS
  • Study the derivation of the electric potential of an infinite line charge
  • Learn about the concept of electric field lines and their implications
  • Explore the differences between constant and variable electric fields
  • Investigate the applications of electric fields in real-world scenarios
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Sarah Kumar
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If the electric field of a line charge at a distance 'a' is µ/2Π ε0a (µ is linear charge density), then the potential at that point should be µ/2Π ε0 (since potential = electric field x distance). This means that the potential is constant at every point around the line of charge. Hence, this means there is no potential difference between any two points around the line of charge. So, no work should be required to move a small charge from one point to another point around a line of charge. Is this conclusion correct?
 
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Sarah Kumar said:
(since potential = electric field x distance)
That formula only works for constant electric fields with zero potential at zero distance, but nowhere else.

By the way: Please put brackets around denominators, otherwise it is difficult to tell where the fraction ends.
 

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