Electric Field of Equilateral Triangle

AI Thread Summary
To determine the electric field at the center of an equilateral triangle with a +2.0μC charge at one vertex and -4μC charges at the other two vertices, the formula E=kQ/r^2 is applied. The user calculated the vector components of the electric fields produced by each charge and summed them to find the resultant electric field. Confirmation from peers indicates that the methodology and calculations are correct. The discussion emphasizes the importance of vector addition in electric field calculations. Overall, the approach taken appears sound and accurate.
Brendan Webb
Messages
26
Reaction score
0

Homework Statement


Consider an equilateral triangle of side 15.6cm. A charge of +2.0μC is placed at one vertex and charges -4μC each are placed at the two. Determine the electric field at the centre of the triangle.

Homework Equations


E=kQ/r^2

The Attempt at a Solution


I am hoping someone can check my methodology and possibly my answer too and let me know if it looks correct. I calculated the components of the vectors and added them and I believe I have it correct.
Part 1 of Question 4.jpg
Part 2 of Question 4.jpg


Thanks
 
Physics news on Phys.org
Your methodology and numbers are correct.
 
Thanks!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top