Electric field produced by 2 point charges

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SUMMARY

The discussion centers on calculating the total electric field at point P due to two point charges, each with a charge of -2.78x10^-10 C. The electric field produced by charge A at point P is 40.0 N/C directed south, while the electric field produced by charge B, located 0.250 m south of A, is 10 N/C directed south. The net electric field at point P is the sum of these two fields, resulting in a total magnitude of 50 N/C directed south.

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  • Familiarity with Coulomb's law and electric field equations
  • Knowledge of vector addition in physics
  • Basic algebra for calculations
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Homework Statement



A small object A, with a charge of -2.78x10^-10 C, creates an electric field. At a point P located 0.250 m directly north of A, the field has a value of 40.0 N/C directed to the south. If a second object B with the same charge as A is placed at 0.250 m south of A (so that objects A and B and point P follow a straight line), what is the magnitude of the total electric field produced by the two objects at P?

So basically:

B<----0.250m----A<----0.250m---->P

Not N-S but same idea.

Homework Equations



E=k(q/r^2)

The Attempt at a Solution



Well, I don't know if electric fields add like vectors. I worked out the electric field produced by B, at point P, is about 10 N/C south. Given its only asking for magnitude, would it be correct to add the two fields together to get the net field at point P to be 50 N/C?
 
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Took a stab at it. I was correct. Thanks regardless.
 

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