Electric Field Strength & Work Calculation: 520V, .8cm

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The discussion centers on calculating the electric field strength and work required to move an electron between two plates with a potential difference of 520V and a distance of 0.80cm. The electric field strength can be determined using the formula E = V/d, resulting in an electric field of 6500 V/m directed from the positive to the negative plate. To calculate the work needed to move an electron, the equation W = qV is applied, where q is the charge of the electron. The participants emphasize the importance of distinguishing between electric potential and electric field in the calculations. Clear understanding of these concepts is crucial for solving the problem accurately.
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Homework Statement


The potential difference between two plates below is 520V. The distance between these two plates is .80cm. (A)What is the strength and direction of the electric field between the two plates? (B) How much work is required to move one more electron to the negative plate?


Homework Equations


NOT SURE IF THESE ARE RELEVANT>
Electric Potential Difference=F/q


The Attempt at a Solution


?
 
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Your equation is not right. That's not E as in electric potential it is E as in electric field. Try looking up potential difference.
 

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