Electric Fields Question (deflection? :S? and more)

AI Thread Summary
An electron enters a parallel plate apparatus with a potential difference of 600V, moving at a speed of 8.0 x 10^7 m/s. To find the vertical deflection, the time taken to travel 10 cm and the electric field between the plates must be calculated first. The force on the electron is determined to find its acceleration, treating it as a projectile to calculate vertical deflection. For the final velocity, the horizontal speed remains constant while the vertical velocity is derived from the time of travel. The discussion concludes with the user successfully solving both parts of the problem.
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Homework Statement



An electron enters a parallel plate apparatus 10cm long and 2.0cm wide, moving horizontally at 8.0 x 10^7 m/s.

If the potential difference acrros the plates is 600V:

a) the vertical deflection of the electron from its original path.
b) the velocity with which it leaves the parallel plate apparatus, inboth magnitude and direction.

Homework Equations



I'm not sure which are relavent. I tried in corporting all motion equations.

The Attempt at a Solution



There are so many ways I tried to solve this question

I already know the answer to it, but it seems impossible to get it.

0.41m
and 8x10^7m/s (right5down)

I don't expect you to solve them all for me (although it would be much helpful) , but please help me start in the right direction.

Thank you
 
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First of all find the time taken by the electron to cover 10 cm.
Find the electric field between the plates. Then force on the electron. Using mass of the electron, find the acceleration of it. Now treat the electron as a projectile,and find the vertical deflection.
 
okay, what do you the electric field?

the intensity? v/d?
 
Yes. v/d.
What is F? What is a?
 
okay i got the answer to a) finally! :D

now b... hm...
 
how would i start this one.?

i tried..

v2^2=v1^2+2ad
 
Initially there is no vertical velocity. SO vi = 0.
Find the time t taken by the electron to travel 10 cm.
Find the vertical velocity after t s.
Horizontal velocity remains constant. Hence find the resultant velocity.
 
i solved finally, thank you.
 

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