Electric Flux through the semisphere

Click For Summary

Homework Help Overview

The discussion revolves around calculating electric flux through a semisphere in the presence of an electric field aligned with the X-axis. Participants explore the relationship between the electric field and the geometry of the semisphere.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for electric flux and its dependence on the orientation of the electric field relative to the surface area. Questions arise regarding the flux through a complete sphere and comparisons to other geometries, such as a cube.

Discussion Status

The discussion includes various interpretations of electric flux in different scenarios, with some participants suggesting that the flux through a sphere is zero under certain conditions. Guidance is offered regarding the implications of having or not having charge within the sphere.

Contextual Notes

Participants reference specific configurations of electric fields and geometries, noting assumptions about the presence of charge and the implications for calculating flux. There is an acknowledgment of the relationship between the electric field direction and the surface area orientation.

YoungILoveYou
Messages
10
Reaction score
0
Hello, if we have an electric field E parallel to X axis and a semisphere with axis parallel to X axis, which is the electric flux through the semisphere?
 
Physics news on Phys.org
YoungILoveYou said:
Hello, if we have an electric field E parallel to X axis and a semisphere with axis parallel to X axis, which is the electric flux through the semisphere?
The flux is:

[tex]\phi = \int E\cdot dA[/tex]

Since flux is a dot product of the field and area, the flux through the semisphere is the same as the flux through the projection of the semisphere onto the yz plane (which is perpendicular to x axis).

AM
 
Yes, if there's no charge inside it, which there wouldn't be with that field, I think. If there is a charge inside the sphere, the flux is Q/epsilon0.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
Replies
20
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
11
Views
2K
Replies
26
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K