Electric force of attraction between forces.

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SUMMARY

The electric force of attraction between charges of 3 C and -10 C separated by a distance of 5 m is calculated using Coulomb's Law, represented by the equation F = k x (Q x q / r^2). The correct calculation yields a force of 1.08 x 1010 N, confirming that the initial confusion stemmed from the omission of the Coulomb's constant (k). The final result of 1.08 x 1010 N is indeed accurate.

PREREQUISITES
  • Coulomb's Law
  • Coulomb's constant (k = 8.99 x 109 N m2/C2)
  • Basic algebra for manipulating equations
  • Understanding of electric charge units (Coulombs)
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  • Study the concept of electric fields and forces
  • Learn about the significance of Coulomb's constant in electrostatics
  • Explore advanced topics in electrostatics, such as electric potential energy
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Students in physics, electrical engineers, and anyone studying electrostatics or electric forces will benefit from this discussion.

astru025
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Problem:
What is the electric force of attraction between charges of 3 C and -10 C separated by a distance of 5 m?

Equation: F= k x (Q x q / r^2)
3 x -10 / 5^2 = -1.2 x 8.99E9 = 1.08 E10 N.

Using this equation and the answer I found, I still am getting the wrong answer. Not sure what I am doing wrong but any help would be nice!
 
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Your calculation does not make sense.
3x(-10)/5^2 does not give that number you show there.
You forgot to include k?
The final result looks OK.
 
So 1.08 E10 is the right answer?
 

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