Electric force of Van de Graaff generator problem.

AI Thread Summary
The discussion revolves around calculating the electric force on a proton at the surface of a Van de Graaff generator, where the proton accelerates at 1.45 x 10^12 m/s². To find the electric force, the formula F=ma is applied, with 'm' being the mass of the proton and 'a' its acceleration. Additionally, the magnitude and direction of the electric field at the generator's surface can be determined using the relationship E=F/q, where 'q' is the charge of the proton. The initial confusion about the problem highlights the need for clarity on applying basic physics principles. Understanding these calculations is essential for grasping the functioning of Van de Graaff generators.
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A Van de Graaff generator is charged so that a proton at its surface accelerates radially outward at 1.45 10^12 m/s2.

Find the following.
(a) the magnitude of the electric force on the proton at that instant magnitude

(b) the magnitude and direction of the electric field at the surface of the generator


I am major stumped... Thanks for helping!
 
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I'm not too sure about Van de Graaff generators but isn't this a simple F=ma=qE question?
 

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