Electric Potential: Calculating Midway Point

AI Thread Summary
To calculate the electric potential at the midpoint between two charges (7.0 microC and 3.0 microC) that are 3.0 m apart, the potentials from both charges must be added together. The relevant equations are Va=Va1+Va2 and V=Kq/r, where K is the electrostatic constant. Since electric potential is a scalar quantity, the contributions from both charges are summed directly, rather than subtracted. The discussion clarifies a common misconception about the midpoint reference, emphasizing that the point, not the charge, is halfway between them. Understanding this distinction is crucial for accurate calculations.
synergix
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Homework Statement



What is the electric potential at the point midway between charges of 7.0 microC and 3.0microC which are 3.0 m apart?

Homework Equations



Va=Va1+-Va2

V= Kq/r

The Attempt at a Solution


I know how to do the calculations I am just not sure about how to add the potentials I am pretty sure that since they are both positive and the charge is halfway between them then the electrical potential will be the difference between the two is that correct?
 
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synergix said:

Homework Statement



What is the electric potential at the point midway between charges of 7.0 microC and 3.0microC which are 3.0 m apart?

Homework Equations



Va=Va1+-Va2

V= Kq/r

The Attempt at a Solution


I know how to do the calculations I am just not sure about how to add the potentials I am pretty sure that since they are both positive and the charge is halfway between them then the electrical potential will be the difference between the two is that correct?

Your last sentence has a typo in it. You say "the charge is halfway between them" You meant to say "the point is halfway between them" There is a difference between the implications of these two phrases.

Putting that aside, since the electric potential is a scalar (not a vector) you simply add the two potentials as indicated in your first equation. If you were adding up the electric fields, where there is a directional property to take into account because the electric field is represented by a vector then you would end up with a subtraction (in this case).
 
ahh yes thank you.
 
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