Electric Potential - Conceptual question

AI Thread Summary
The discussion revolves around calculating the distance to a point charge and its magnitude based on given electric field and potential values. The solutions provided indicate a distance of 6 meters and a charge of -2 micro-Coulombs. A key question raised is the visual concept behind determining the charge's negativity when using the electric field equation, E = kq/r^2. It is clarified that the sign of the charge cannot be determined solely from the electric field without knowing its direction, but the negative potential confirms the charge's negativity. Therefore, the negative charge is established as a fact based on the provided potential.
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Homework Statement



At a certain distance from a point charge, the magnitude of the electric field is 500 V/m and the electric potential is -3.00 kV. (a) What is the distance to the charge? (b) What is the magnitude of the charge?

Homework Equations



The Attempt at a Solution



a) 6 meters
b) -2 micro-Coulombs
*These are correct, I mention this fact cause I don't want you to have to waste your time checking so.

My question is: for part b, if you solve for Q, the magnitude of charge, from E instead of V (E = kq/r^2), what is the visual concept behind why the charge is negative? Because obviously if you solve from V, you will get a negative 2 uC.

Of course the book asks for magnitude anyway, but the answer key gives the negative sign as well. I want to understand the concept behind it.
 
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EngineerHead said:
My question is: for part b, if you solve for Q, the magnitude of charge, from E instead of V (E = kq/r^2), what is the visual concept behind why the charge is negative?
You cannot tell the sign of Q just using E, since you were not told the direction of the field.
 
Thank you, and just to verify - because of the potential given, it is a fact that the charge is negative?
 
EngineerHead said:
Thank you, and just to verify - because of the potential given, it is a fact that the charge is negative?
Yes.
 
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