Electric potential due to collection of charged particles

AI Thread Summary
The discussion centers on calculating the electric potential at the origin due to two charged particles. The formula used is V = k(q1/r1 + q2/r2), where k is the Coulomb's constant. The initial calculation yielded a potential of -6.87x10^5, but the textbook answer is -8.21x10^5. The discrepancy was identified as an error in the distance used for the first charge, which should be 0.0325 m instead of 0.035 m. The participant resolved the calculation issue and expressed relief at finding the correct answer.
Rijad Hadzic
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Homework Statement


A particle with charge q1 = -6.75x10^-6 is located at (0,3.25x10^-2 m ) and a second particle with charge 3.2x10^-6 is located at (0,-2.75x10^-2 m) what is the electric potential due to the two charges at the origin?

Homework Equations


V = kq/r

The Attempt at a Solution



So at the origin the potential should be kq1/r1 + kq2/r2 = k(q1/r1 + q2/r2)

plugging in, (8.99x10^9)(-1733785 + 1046109) = -6.87x10^5

but my book is telling me the answer is -8.21x10^5

what am I not taking into account here?
 
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Rijad Hadzic said:
So at the origin the potential should be kq1/r1 + kq2/r2 = k(q1/r1 + q2/r2)
Good.

plugging in, (8.99x10^9)(-1733785 + 1046109)
I don't get the values shown in red.
 
TSny said:
Good.

I don't get the values shown in red.

Strange. I did the calculation a million times exactly like I just did it but I got the answer now... the mechanical task of calculating stuff makes me want to pull out my hair. I hope I don't do this on a test lol.

Anyways thank you..
 
OK, good. For the first charge, it looks like you used a distance of .035 m rather than .0325 m.
 
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