Electric Potential Energy: Work Required to Move 3 Charges Out to Infinity

AI Thread Summary
To calculate the work required to move three charges infinitely far apart, the initial approach involved determining the work for each charge individually using the formula W = -kq1[(q2/r12) + (q3/r13)]. The results for the individual charges were -0.539 J for q1, +0.862 J for q2, and -0.861 J for q3. However, it was clarified that only two charges need to be moved to infinity, and once the first charge is moved, it no longer affects the remaining charges. This insight helped redirect the problem-solving approach effectively. Understanding the interactions between the charges is crucial for accurately calculating the total work required.
ayreia
Messages
6
Reaction score
0

Homework Statement



Three charges are distributed as follows:

http://tinypic.com/r/1fviq0/5

How much work must an external force do to move them infinitely far from each other?

Homework Equations



W = -\DeltaU = (kq_{1}q_{2})/r

The Attempt at a Solution



So what I did was find the work needed to move each individual charge out to infinity using

W = -kq_{1} [(q_{2}/r_{12}) + (q_{3}/r_{13})].

For q_{1} this gave me -0.539 J, q_{2} +0.862 J, and q_{3} -0.861 J. I thought I could just add them together to get the total work, but this is incorrect. I'm completely stumped now as to how to proceed. Can someone point me in the right direction? Thanks a lot!
 
Physics news on Phys.org
hi ayreia! :smile:

you only need to move two of them to infinity, don't you? :wink:

(also, once you've moved the first one, you can forget about it when you move the second one)
 
Oh, right! That makes sense, thanks a lot! :D
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top