How Fast Does an Electron Move Towards a Charged Plane?

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SUMMARY

An electron released from rest at a distance of 4 meters from an infinite plane of positive charge experiences a constant electric field of 100 V/m. The force acting on the electron is calculated using the formula F = E * Q, resulting in a force of 1.6 x 10^-13 N. By applying Newton's second law (F = ma), the acceleration of the electron is determined to be 1.756 x 10^13 m/s². The kinematic equation V_f² = V_i² + 2ad is identified as the appropriate method to calculate the final velocity of the electron upon collision with the charged plane.

PREREQUISITES
  • Understanding of electric fields and forces (Electric Field, E = 100 V/m)
  • Knowledge of Newton's second law (F = ma)
  • Familiarity with kinematic equations (V_f² = V_i² + 2ad)
  • Basic concepts of charge and mass (Charge of electron = 1.6 x 10^-19 C, Mass of electron = 9.11 x 10^-31 kg)
NEXT STEPS
  • Calculate the final velocity of the electron using the kinematic equation V_f² = V_i² + 2ad
  • Explore the implications of electric fields on particle motion in physics
  • Study the relationship between electric potential and electric fields
  • Investigate the effects of varying electric field strengths on charged particles
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the dynamics of charged particles in electric fields.

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Homework Statement



An electron is released from rest 4m from an infinite plane of positive charge. The plane produces an electric field with a constant magnitude of 100 V/m. How fast is the electron moving when it collides with the plane? Mass of E = 9.11x10^-31kg.

Homework Equations



Not sure... Ui + Ki = Uf + Kf?

The Attempt at a Solution

 
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You are given the electric field, not the voltage at the point so you can't use conservation of energy. Remember, electric field * charge = force on charge. You can use this to find the force on the electron, and then use one of the kinematics equations so solve for the speed.
 
kkrizka said:
You are given the electric field, not the voltage at the point so you can't use conservation of energy. Remember, electric field * charge = force on charge. You can use this to find the force on the electron, and then use one of the kinematics equations so solve for the speed.

Ok so I did F=EfxQ...(100 v/m)(1.6x10-19) = 1.6x10^-13 J. And then F=ma so A = (1.6x10^-17)/(9.11x10-31) = 1.756x10^13 m/s...

I'm lost what to do after that...what kinematic equation should i use?
 
The one that involves initial, final velocities, acceleration and displacement. I believe it is
V_f^2 = V_i^2 + 2ad
 

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