Electric Potential- quick question about process

AI Thread Summary
The discussion revolves around calculating the distance of closest approach for an alpha particle colliding with a lead nucleus, given the alpha particle's kinetic energy of 10 MeV. A key point raised is the conversion of energy from MeV to joules, specifically why the kinetic energy is multiplied by 1.6e-19. This conversion is necessary to use the energy in the electric potential equation, V=kq/r. Participants emphasize the importance of understanding this conversion for solving similar physics problems. The conversation highlights the educational value of collaborative problem-solving in physics.
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Electric Potential-- quick question about process

Homework Statement



An alpha particle with kinetic energy 10 MeV makes a head-on collision with a lead nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)

Homework Equations



V=kq/r

The Attempt at a Solution



http://www.solvephysics.com/electricity_problem26.shtml
I tried going by this site to solve this. I would just like to know why in the Einitial equation they multiply the 10MeV by 1.6e-19. Why do they do that? I don't understand.

Thanks!
 
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SuperCass said:

Homework Statement



An alpha particle with kinetic energy 10 MeV makes a head-on collision with a lead nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)

Homework Equations



V=kq/r

The Attempt at a Solution



http://www.solvephysics.com/electricity_problem26.shtml
I tried going by this site to solve this. I would just like to know why in the Einitial equation they multiply the 10MeV by 1.6e-19. Why do they do that? I don't understand.

Thanks!


http://en.wikipedia.org/wiki/Electronvolt
 


Thank you so much, I would have never gotten that on my own!
 


SuperCass said:
Thank you so much, I would have never gotten that on my own!

It should be in your textbook as well.
 
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