# Electrical circuit with resistors problem

1. Jun 16, 2011

### zeev55

1. what is the Electric current that goes through the ampermeter (see the picture)
http://imageshack.us/photo/my-images/545/66683625.png"

[PLAIN]http://img545.imageshack.us/img545/4379/66683625.png [Broken]

2. the current that goes through the 2R resistor is $\frac{4\epsilon}{13R}.$ (I dident find it myself , it was the answer of a similar problem in which the subject was the resistor not the ampermeter.)

the answer given by the text book: I(A)=$\frac{6\epsilon}{13R}$

Last edited by a moderator: May 5, 2017
2. Jun 16, 2011

### thepatient

You'll have to use the loop rule and junction rule. At each junction of wire, the current in is equal to the current out. Also, if you add up the changes in potential within a closed loop in the circuit, they should add up to zero. For example, if you start at point A, you move through resistors or batteries throughout the loop and return back to point A, the sum of those changes in potential should be zero,.

3. Jun 16, 2011

### Staff: Mentor

It looks like the answer attributed to the book is not correct for this circuit. So if you're despairing of reproducing that answer, you can relax a bit. There is still hope!

Zeev55, what have you tried?

4. Jun 16, 2011

### zeev55

nothing worth writing in here.. I dont mean to sound rude but it would really help me if someone write the full answer to the problem.
thank you

5. Jun 16, 2011

### Staff: Mentor

Alack and alas, that is not what we do here. We can help you to solve the problem, but not solve the problem for you.

Why not have a go at either loop equations or some other approach to the problem, and we can then see how to guide you.

It might (or might not!) be of interest to know that the problem can be solved with a bit of study of how the currents divide and add. Keep in mind that the Ammeter doesn't influence the circuit in any way: it just tells you the current flowing through it.