Solving Electrical Currents Equations

[neb1627]

9 - 2.7(I) - .038(I) = 0
13 - .023(I) + 2.7(I) - 9 = 0

I don't know how the dead battery effects it and how to figure out the
different currents thru the different resistors

 

[DaMastaofFisix]

Kirchoff Loop rules. Remeber that when you jump start a car, you are "restarting" the battery as well.

 

[kyle8921]

I would approach this problem by first defining the variables and units involved. In this case, the variables are the electrical currents (I) and the resistors (in ohms). The units for current are typically measured in amperes (A) and for resistance in ohms (Ω). It is also important to clarify the context and setup of the problem, as it seems to involve a circuit with multiple resistors.

Next, I would use the given equations to solve for the unknown current values. In the first equation, we have 9 - 2.7(I) - .038(I) = 0. Simplifying this, we get 9 - 2.738(I) = 0. This can be further simplified to 2.738(I) = 9, and solving for I gives us a value of approximately 3.29 A.

Similarly, in the second equation, we have 13 - .023(I) + 2.7(I) - 9 = 0. Simplifying, we get 13 - 6.7(I) = 0. Solving for I gives us a value of approximately 1.94 A.

To address the concern about the dead battery, I would need more information about the circuit and the specific resistors involved to accurately determine its effect on the overall currents. However, in general, a dead battery would likely decrease the overall current in the circuit.

To find the currents through the different resistors, we would need to use Ohm's law, which states that the current (I) through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R). We would also need to know the voltage and resistance values for each individual resistor in the circuit.

In conclusion, solving electrical current equations involves defining variables and units, simplifying equations, and using Ohm's law to find the current through each resistor. Further information about the circuit and its components would be needed to accurately determine the effect of a dead battery on the currents.