How Do Electrical Equations Help Calculate Charge and Electron Flow in Circuits?

[runicle]

Can you please explain me in lamens terms what are these variables names and what they give:
-
1c=6.24 * 10^18
e=1.60 * 10^-19
Q=Ne
Fe=KQ1Q2/d^2
I=Q/T
1A = 1C/1s
-
And How would i do this question with the stuff i have written above this line?
-
A current of 0.82 A flows through an electric lamp for 10 min. In that time how much charge passes a given spot in the filament expressed in
(a)Coulombs
(b)Electrons
-
For (a) i think I need to use 1A = 1C/1s
So C=A*S
-C=0.82 A (600s)
-C=492
But in the back of my book its -492 explain what i did wrong
-
For (b) I think i don't know what to use I'm

 

[ranger]

1c=6.24 * 10^18
One Coulomb is 6.24 x 10^18 electrons (Sould help you with part b)

Can you please explain me in lamens terms what are these variables names and what they give:

Fe=KQ1Q2/d^2

This is known as coulomb's law
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elefor.html#c1

 

[quicknote]

sorry

Hi there,

Sure, I'd be happy to explain these variables and equations to you in simpler terms.

1c = 6.24 * 10^18 represents the charge of an electron, which is a tiny particle that makes up atoms. It is a very small amount of charge, so we use scientific notation (6.24 * 10^18 means 6.24 multiplied by 10 raised to the power of 18).

e = 1.60 * 10^-19 represents the elementary charge, which is the smallest possible amount of charge that an object can have. It is also a very small amount, so we use scientific notation.

Q = Ne means that the total charge (Q) is equal to the number of electrons (N) multiplied by the charge of each electron (e). This is a way to calculate the total charge of a group of electrons.

Fe = KQ1Q2/d^2 is an equation that represents the force of attraction or repulsion between two charged objects. K is a constant that depends on the medium between the objects, Q1 and Q2 are the charges of the objects, and d is the distance between them.

I = Q/T is an equation that relates current (I) to charge (Q) and time (T). It means that the current is equal to the total charge passing through a point divided by the time it takes to pass through.

1A = 1C/1s is simply a conversion factor between amperes (A) and coulombs (C). It means that 1 ampere is equal to 1 coulomb per second.

Now, let's solve the question using the equations you have listed.

(a) To find the amount of charge passing through the filament in coulombs, we can use the equation I = Q/T. We know that the current (I) is 0.82 A and the time (T) is 10 minutes = 600 seconds. So, we can rearrange the equation to solve for Q:

I = Q/T

Q = I * T

Q = 0.82 A * 600 s

Q = 492 C

So, the amount of charge passing through the filament in coulombs is 492 C.

(b) To find the amount of charge passing through the filament in electrons, we can use the equation Q = Ne. We know that the charge of an electron (