Electrical field outside spherical shell

AI Thread Summary
To find the electric field outside an insulated spherical shell with a surface charge density of σ(θ) = σ0 sin(θ), the total charge on the shell is calculated as Q = π²R²σ0. The user expresses confusion about applying Gauss's Law to determine the electric field at point z = R. They suggest considering the integral of dq/r² but are unsure how to proceed. Clarification on using Gauss's Law in this context is sought, indicating a need for guidance in applying the correct principles. The discussion highlights the challenge of calculating the electric field for non-uniform charge distributions.
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Homework Statement


An insulated spherical shell with its center in the origin and radius R has a surface charge density of \sigma(\theta)=\sigma_0\sin(\theta) when \theta is the angle from the z axis. Calculate the electrical field outside the shell at point z=R.


Homework Equations



Gauss's Law
\int\int{\vec{E}\cdot\vec{dS}}=4\pi{Q_{in}}


The Attempt at a Solution



I tried first calculating the overall charge of the spherical shell:
Q=R^2\int_0^{2\pi}\sigma_0\sin^2\theta{d\theta}\int_0^\pi{d\phi}=\frac{R^2\sigma_0}{2}\int_0^{2\pi}(1-\cos{2\theta})d\theta\cdot\pi=\frac{1}{2}\pi{R^2}\sigma_0\cdot{2\pi}=\pi^2R^2\sigma_0
However, I don't see how Gauss's Law can help me find the electrical field at that specific point.

Please help!
 
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anyone?

Can someone please help??

Perhaps I should somehow calculate \int{\frac{dq}{r^2}} ?
 
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