Electrical Science - LR Time Constant & Voltage Drops

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SUMMARY

The discussion focuses on calculating the LR time constant and voltage drops in a circuit consisting of a 0.2 H inductor and a 330 Ω resistor connected to a 12V DC supply. The time constant (T) is determined using the formula T = L/R, yielding a value of 0.606 ms. The resistance needed to replace the inductor to achieve a time constant of 0.55 ms is calculated to be approximately 33.64 Ω. The user seeks assistance in finding equations for voltage drops across the inductor and resistor after specified time constants.

PREREQUISITES
  • Understanding of RL circuit theory
  • Familiarity with the time constant formula T = L/R
  • Knowledge of voltage drop calculations in series circuits
  • Basic proficiency in electrical engineering concepts
NEXT STEPS
  • Research the voltage decay equation for an inductor in an RL circuit
  • Learn how to calculate voltage drops across components after multiple time constants
  • Explore the impact of varying resistance on the time constant in RL circuits
  • Study practical applications of RL circuits in electronic devices
USEFUL FOR

Electrical engineers, students studying circuit theory, and anyone involved in designing or analyzing RL circuits will benefit from this discussion.

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Electrical Science -- LR Time Constant & Voltage Drops

1. An inductor of negligible resistance and an inductance of 0.2 H is
connected in series with a 330 Ω resistor to a 12V d.c. supply.
Determine:

(a) the time constant of the circuit
(b) the voltage drop across the inductor after two time constants
(c) the voltage drop across the resistor after three time constants
(d) the resistance of a 0.2 H coil used to replace the inductor if the
circuit’s time constant falls to 0.55 ms.

Relevant Equations:
a) T=L/R
b)?
c)?
d)T=L/R

Attempt:

a) T=L/R
T= 0.2/330
T= 0.000606
T= 0.606 ms
*Quite confident on this one.

b&c) I'm really struggling trying to ascertain what equations I need to calculate these two answers and that is where I need the help.

d) T=L/R
R=L/T
R= 0.2/0.00055
R= 363.63 Ohms
Resistance of coil = 363.63 - 330 = 33.64 Ohms
*Quite confident on this one too.

If someone has the time to confirm my answers for a) & d) look ok, and to help with the equations and path I need to take to calculate b) & c) it would be much appreciated.

Thanks in advance :)

 
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Thanks, all sorted now... I appreciate your response.
 

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