Can a Charged Particle Move in a Straight Line in a Nonzero Magnetic Field?

AI Thread Summary
A charged particle can move in a straight line in a nonzero magnetic field if the magnetic force acting on it is zero. This occurs when the velocity of the particle is parallel to the magnetic field, resulting in no perpendicular component of the field. The magnetic force is calculated using F=qvB, where B is the component of the magnetic field perpendicular to the particle's velocity. If the particle's motion is straight, the magnetic force must be zero, indicating that the magnetic field can exist without affecting the particle's trajectory. The discussion emphasizes the importance of considering the direction of both the velocity and the magnetic field.
Rsealey
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Homework Statement


A charged particle moves in a straight line through a particular region of space. Could there be a nonzero magnetic field in this region? In either case, include a sketch as well as prose in your justification.


Homework Equations





The Attempt at a Solution


The force that a magnetic field exerts on a charged particle moving through it is given by F=qvB, sin theta = qvB where B is the component of the field perpendicular to the particle’s velocity. Since the particle moves in a straight line the magnetic force must be zero.
 
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Rsealey said:
The force that a magnetic field exerts on a charged particle moving through it is given by F=qvB, sin theta = qvB where B is the component of the field perpendicular to the particle’s velocity.
OK.

Since the particle moves in a straight line the magnetic force must be zero.
The magnetic force is zero. What about the field?
 
Rsealey said:
The force that a magnetic field exerts on a charged particle moving through it is given by ##F=qvB## ##sin (\theta )##[/color] ##= qvB## where ##B## is the component of the field perpendicular to the particle’s velocity[/color]. Since the particle moves in a straight line the magnetic force must be zero.

Hmmm...
Another way to look at that relationship is ##\vec{F}=q\vec{v}\times \vec{B}##
It's essentially the same relationship, but I think you're looking at it wrong by only looking at the perpendicular part of the magnetic field.
 
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