- #1
abeltyukov
- 32
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Hi,
In a simple model of the hydrogen atom, the electron moves in a circular orbit of radius 0.053 nm around a stationary proton. How many revolutions per second does the electron make?
F = (kq1q2)/r^2 = (mv^2)/r
v = wr
Charge of electron = -1.602 x 10^-19 C
Charge of proton = 1.602 x 10^-19 C
Mass of electron = 9.109 x 10^-31 kg
[(8.999 x 10^9)(1.602 x 10^-19)(1.602 x 10^-19)] / (0.053 x 10^-9) = (mv^2)/r
v = 0.002187 m/s
v = wr
0.002187 = w(0.053 x 10^-9)
w = 41267720.67
Any ideas on what I am doing wrong? Thanks!
Homework Statement
In a simple model of the hydrogen atom, the electron moves in a circular orbit of radius 0.053 nm around a stationary proton. How many revolutions per second does the electron make?
Homework Equations
F = (kq1q2)/r^2 = (mv^2)/r
v = wr
The Attempt at a Solution
Charge of electron = -1.602 x 10^-19 C
Charge of proton = 1.602 x 10^-19 C
Mass of electron = 9.109 x 10^-31 kg
[(8.999 x 10^9)(1.602 x 10^-19)(1.602 x 10^-19)] / (0.053 x 10^-9) = (mv^2)/r
v = 0.002187 m/s
v = wr
0.002187 = w(0.053 x 10^-9)
w = 41267720.67
Any ideas on what I am doing wrong? Thanks!