What is the electro-static energy of a sphere with uniform charge density?

  • Thread starter Thread starter Parallel
  • Start date Start date
  • Tags Tags
    Energy
AI Thread Summary
The discussion revolves around calculating the electro-static energy of a uniformly charged sphere, initially stated as (3/5)kQ/R. The user seeks clarification on integrating the potential over the volume, questioning whether to integrate from r=0 to r=infinity, given that charge density is zero outside the sphere. It is confirmed that integration should only occur from r=0 to r=R, as the potential outside the sphere contributes nothing. The user also realizes a mistake in the energy formula, correcting it to (3/5)kQ^2/R to ensure proper unit consistency. The conversation concludes with acknowledgment of the importance of careful calculations in physics.
Parallel
Messages
42
Reaction score
0

Homework Statement


hello
I have a question,it's not homework related..I know the electro-static energy of a sphere is:(3/5)kQ/R

I tried to calculate it today using the expression:
U = 1/2 * integral (phi * rho dV)
where: phi is the potential, rho is charge density(uniform), dV is the volume element.

it's not hard to calculate the potential everywhere in space,but my problem is when I integrate over volume elements (4*pi*r^2 dr) should I integrate over:
r=0 to r=infinity? it doesn't seem reasonable because rho=0 outside the sphere.

anyway I tried to do that,i.e integrating over r=0 to r=R using the potential inside the sphere,but I didnt get the correct answer.

I would love to get some help with this.

thanks.
 
Physics news on Phys.org
You're right: the integral should go over all of space (r = 0 to r = infinity), but since rho is 0 outside of the sphere, all of the integration that goes on outside the sphere amounts to 0. That's why it's OK to only integrate inside the sphere (r = 0 to r = R). So you should be set. If it's not coming out, check your math and your equations again. Is the sphere uniformly charged? Is it a hollow shell with the charge just on the outside? Make sure you know which situation you're looking at.

P.S. I'm guessing that you're equation for the energy in the sphere ( (3/5)kQ/R ) is off. There should be a Q^2 term in there to make the units work...right now you have the units of an electric potential...which is potential energy per unit charge...they're closely related, but there's a distinct difference.
 
Last edited:
of course I meant (3/5)kQ^2/R :)

and you were right,I had a stupid math mistake(I really hate those)

thanks alot.
 
Parallel said:
and you were right,I had a stupid math mistake(I really hate those)

Those will get you every time! Gotta love it :-p Glad it worked out though!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top