Electrodynamics: Solve the differential equation

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Homework Help Overview

The discussion revolves around solving a differential equation derived from Kirchhoff's laws in the context of a direct current (DC) circuit involving capacitors and resistors. The original poster presents the equation and their attempts to find the charge Q(t) over time.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss differentiating the original equation to derive a second-order differential equation. There are questions about how to determine the constants in the solution, particularly the initial conditions needed for A and B.

Discussion Status

Some participants have provided guidance on the need for initial conditions to solve for the constants in the equation. The original poster expresses uncertainty about the initial current and its implications for finding a particular solution. There is an indication that the discussion is progressing towards identifying necessary conditions for a complete solution.

Contextual Notes

The original poster notes a lack of information regarding the initial current, which is a critical piece for solving the differential equation completely. This uncertainty is acknowledged by participants in the thread.

Niles
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Homework Statement


Hi all.

Please take a look at the attached circuit, where the current is direct (i.e. DC).

I have found the following differential equation using Kirchoff's laws:

[tex] V=\frac{R_1+R_2}{R_2C}Q+R_1\frac{dQ}{dt}.[/tex]

I wish to solve this equation, and thus to find Q(t).

The Attempt at a Solution



First I differentiate with respect to t to obtain:[tex] 0=\frac{R_1+R_2}{R_2C}\frac{dQ}{dt}+R_1\frac{d^2Q}{dt^2}.[/tex]

Solving this gives me the following:[tex] Q(t)=A+B\exp\left( {\frac{R_2+R_1}{R_2R_1C}t} \right),[/tex]

where I have used the fact that Q(t=0)=0 to find that B=-A. But how do I find A?

Thanks in advance.Niles.
 

Attachments

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    circuit.png
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Obtain an expression for the current, then find the charge.

Just use the fact the i = dq/dt and di/dt = d^2q/dt^2 and use separation of variables.
 
Niles said:
[tex] Q(t)=A+B\exp\left( {\frac{R_2+R_1}{R_2R_1C}t} \right),[/tex]

where I have used the fact that Q(t=0)=0 to find that B=-A. But how do I find A?

You need two initial conditions to find the two constants. One is Q(0), the other one? What is the initial current?
 
I am not told what I(0) is, but I guess it is zero. But how will this help me?

And if I solve for I instead of Q, then how can I find the particular solution?
 
Ok, I solved it. I just have to find the final charge on the capacitor, and that is the particular solution.
 

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